The equation for photon energy, E, is E=hcλ where h = 6.626×10−34 J⋅s (Planck's constant) and c = 2.99×108 m/s (the speed of light). What is the wavelength, λ, of a photon that has an energy of E = 3.65×10−19 J ?
Energy of a photon = hc/λ
3.65 x 10^-19 = 6.626 x 10^-34 x 2.99 x 10^8/λ
λ = 6.626 x 10^-34 x 2.99 x 10^8 / 3.65 x 10^ -19
= 5.42 x 10^-7 m.
Hence wavelength of photon is 5.42 x 10^-7 m.
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The required wavelength of the light is 5.42 x 10⁻⁷ m.
The wavelength (λ) is define as a waveform signal conveyed in space or along a wire is the distance between identical points (adjacent crests) in adjacent cycles.
And it will be calculated as:
E = hc/λ, where
On putting these values, we get
λ = (6.626 x 10⁻³⁴)(2.9 × 10⁸) / (3.65 x 10⁻¹⁹)
λ = 5.42 x 10⁻⁷ m
Hence required wavelength is 5.42 x 10⁻⁷ m.
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