Answer: \(9x^8, 25x^{12} , 36x^{16}\)
Step-by-step explanation:
Let's check all the monomials
\(6x^2\)
Here 6 is not square digit, hence this monomial is not a perfect square.
\(9x^8=(3)^2(x^4)^2 =(3x^4)^2\)
Here 9 is a square digit and the power of x i.e. 8 is multiple of 2 .
Hence, this monomial is a perfect square.
\(16x^9\)
Here 16 is a square digit but the power of x i.e.9 is not multiple of 2 .
Hence, this monomial is not a perfect square.
\(25x^{12} =(5x^6)^2\)
Here 25 is a square digit and the power of x i.e. 12 is multiple of 2 .
Hence, this monomial is a perfect square.
\(36x^{16}=(6x^8)^2\)
Here 36 is a square digit and the power of x i.e.16 is multiple of 2 .
Hence, this monomial is a perfect square.
