How many atoms are in 0.075 mol of titanium?
The mass of titanium is = 47,867 g/1mol
Applying the rule of avrogado
1mol _______ 6,023 × 10^(23) at
0,075mol ___ x
X . 1mol = 0,075mol . 6,023 . 10^(23)at
X = 0,075 . 6,023 . 10^(23) at
X = 4,51 . 10^(22) atoms
Hope this helps
Answer: The number of atoms in given amount of titanium are \(4.52\times 10^{22}\)
Explanation:
We are given:
Moles of titanium = 0.075 moles
According to mole concept:
1 mole of an element contains \(6.022\times 10^{23}\) number of atoms
So, 0.075 moles of titanium will contain = \((0.075\times 6.022\times 10^{23})=4.52\times 10^{22}\) number of atoms
Hence, the number of atoms in given amount of titanium are \(4.52\times 10^{22}\)