a student has some $1 bills and $5 bills in his wallet. he has a total of 15 bills that are worth $47. How many of each type of Bill does he have. (using algebra, substitution to solve a problem)
The student would have 8 $5 bills and 7 $1 bills because 58=40 and 71=7 and adding them together makes 47! Hope that helps!
Answer: The student has 7 $1 bills and 8 $5 bills.
Step-by-step explanation: Give that a student has some $1 bills and $5 bills in his wallet. He has a total of 15 bills that are worth $47.
We are to find the number of each type of bills that he has.
Let m and n represents the number of $1 bills and $5 bills respectively.
Then, according to the given information, we have
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and
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From equation (i), we get
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Thus, the student has 7 $1 bills and 8 $5 bills.