we have
\(r(x) = 3x - 1\\s(x) = 2x + 1\)
we know that
the ratio \(\frac{r}{s}(x)\) is equal to
\(\frac{3x-1}{2x+1}\)
for \(x=6\)
substitute the value of x in the equation
\(\frac{3(6)-1}{2(6)+1}\)
therefore
the answer is the first option
\(\frac{3(6)-1}{2(6)+1}\)
