A bullet whose mass is 30.2 g leaves a rifle with a muzzle velocity of 1,000 m/s. It strikes a block of wood (mass 5 kg), initially at rest, and remains embedded in it. After the bullet hits the block, what will be the velocity of the bullet-block system?

A30.2
B1.51
C33.1
D165
E6

f. 7.6

g. 6,000

This problem here is an example of inelastic collision where kinetic energy is not conserved but momentum is. We calculate as follows:

m1v1 + m2v2 = (m1 + m2)v3
v3 = m1v1 + m2v2 / m1 + m2
v3 = (30.2)(1000) + (5000)(0) / (30.2 + 5000)
v3 = 6.00 m/s

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A bullet whose mass is 30.2 g leaves a rifle with a muzzle velocity of 1,000 m/s. It strikes a block of wood (mass 5 kg), initially at rest, and remains embedded in it. After the bullet hits the block, what will be the velocity of the bullet-block system? A30.2B1.51C33.1D165E6 f. 7.6g. 6,000

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