A=? B=8 C=10 Pythagorean practice
any answer choices to choose from so i can help??
\(a^{2}+b^{2}=c^{2}\) So you plug in the numbers:\(a^{2}+8^{2}=10^{2}\)and solve for a:\(a^{2}=36\)\(a=\sqrt{36}[/tex}[tex]a=6\)