Verified Answer :

using
 f1(x)= -x=3t =14

with f2(x) as x=4y

f1(f2)= -x-3y=14
F1(4y)= -(4y)-3y=14
           = -4y-3y=14
           = - 7y=14
           = y= -2

Using the value of y, solve fo rx by entering the value in the original form of f1 or f2

-x-3y=14
-x-3(-2)=14
-x+6=14
x=-8

OR
x=4y
  =4(-2)
  = -8

Thus the solution is (x,y) = (-8,-2)

Solve both equations for one variable.  Since the second equation is already solved for \(x\), we'll solve the other one for \(x\).

\(x=-14-3y\) and \(x=4y\) are our two equations.  

Now we can assume that if \(x = -14-3y\) and \(x=4y\), we can assume that \(-14-3y = 4y\).  If we solve for \(y\), we get that \(y=-2\).  Plug in \(y=-2\) into either one of the equations, I'll use \(x=4y\).  \(x=4(-2)\) so [/tex]x=-8[/tex].  Know we know what \(x\) and \(y\) are, so we can put it in an orderned pair:  (-8,-2)