what is the inverse of "f"if f(x)=^3 sqrtx-5
y=x−5−−−−√3x=y−5−−−−√3
Assuming that the original equation is f(x)= \(\sqrt[3]{x-5}\)the inverse of f(x) is f(y)f(x)= \(\sqrt[3]{x-5}\) y=\(\sqrt[3]{x-5}\)f₋₁(y)= \(\sqrt[3]{y-5}\) x=\(\sqrt[3]{y-5}\) x³= y-5 y=x³+5Thus f₋₁=y=x³+5
