Answer:
The center of the circle is (2, -8)
Step-by-step explanation:
Given : the equation of circle as \((x-2)^2+(y+8)^2=16\)
We have to find the center of the circle whose equation is \((x-2)^2+(y+8)^2=16\)
The general equation of a circle is given as \((x-h)^2+(y-k)^2=r^2\)
Where , (h,k) represents the center of the circle and r represents the radius of the circle.
Comparing the given equation of circle \((x-2)^2+(y+8)^2=16\) with the general we get,
h = 2 , k = -8 and r = 4
Thus \((x-2)^2+(y+8)^2=16\) can be written as \((x-2)^2+(y-(-8))^2=4^2\)
Thus, the center of the circle is (2, -8)
