Answer:
option B is true.
Step-by-step explanation:
We are given that two functions
f(x)=\(sec^2x\) and g(x)=sin x and a line x =\(\frac{\pi}{4}\)
We have to find the area of the region bounded in the first quadrant by x=\({\pi}{4}\) and two functions
We know that the area bounded by two functions
=Integration of region(Upper curve- lower curve)
Therefore, function of sec square x is upper curve and function of sin x is lower function
Therefore, limit of x changing from 0 to \(\frac{\pi}{4}\)
Hence, the area of the region bounded in the first quadrant and two functions is given by
\(=\int_{0}^{\frac{\pi}{4}} (sec^2x-sinx) dx\)
Therefore, option B is true.
