Answer:
The value of given radical \(\sqrt[3]{216}\) is 6.
Step-by-step explanation:
Given :Radical \(\sqrt[3]{216}\)
We have to evaluate the given radical \(\sqrt[3]{216}\)
Consider the given radical \(\sqrt[3]{216}\)
Factored the given number \(216=6^3\)
\(=\sqrt[3]{6^3}\)
Apply radical rule, \(\sqrt[n]{a^n}=a\)
We have,
\(\sqrt[3]{6^3}=6\)
Thus, The value of given radical \(\sqrt[3]{216}\) is 6.
