Amy walks 3 m from her desk to the teacher's desk. From the teacher's desk, she then walks 4 m in the opposite direction to the classroom door. Which table correctly represents both the distance and displacement of Amy's motion?
I don't know what the tables you have look like but her displacement would be -1m
Answer:
distance = 7 m
displacement = 5 m
Explanation:
distance moved by Amy is the total path length that she moved
so it is given as
\(d = d_1 + d_2\)
here we have
\(d_1 = 3 m\)
\(d_2 = 4 m\)
so we have
\(d = 7 m\)
now since both the distance that she moved is perpendicular to each other so total displacement of Amy is given as
\(d = \sqrt{d_1^2 + d_2^2}\)
\(d = \sqrt{3^2 + 4^2} = 5 m\)