Answer:
Option third is correct that is \(6p^3-23p^2+9p+28\)
Explanation:
We have been given two expression \((3p-7)\) and \((2p^2-3p-4)\)
multiplication is to be done simplify the expressions by opening the parenthesis we will get
\(\left(3p-7\right)\left(2p^2-3p-4\right)\)
\(\Rightarrow\)\(3p\cdot \:2p^2+3p\left(-3p\right)+3p\left(-4\right)+\left(-7\right)\cdot \:2p^2+\left(-7\right)\left(-3p\right)+\left(-7\right)\left(-4\right)\)
After simplification we will get
\(\Rightarrow3\cdot \:2p^2p-3\cdot \:3pp-3\cdot \:4p-7\cdot \:2p^2+7\cdot \:3p+7\cdot \:4\)
Further simplification will give the final result
\(\Rightarrow6p^3-23p^2+9p+28\)
