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10020 + 20080 = 300* T
T = 60

Answer:

Option (a)

Explanation:

Let c be the specific heat of water.

According to the principle of caloriemetry.

Heat lost by hot water = heat gained by cold water

200 x c x (70 - T) = 50 x c x (T - 20)

280 - 4T = T - 20

300 = 5T

T = 60 C

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