Answer: It will take 2\(\frac{2}{5}\) minutes to crawl the given distance
Step-by-step explanation:
Given :Ant crawls at the rate 2\(\frac{1}{6}\) ft /min
=\(\frac{12+1}{6}\) ft
=\(\frac{13}{6}\) ft
Distance: 5\(\frac{1}{5}\) ft
=\(\frac{25+1}{5}\) ft
=\(\frac{26}{5}\) ft
Time taken =\(\frac{Distance}{Speed}\)
=\(\frac{26/5}{13/6}\)
\(\frac{26*6}{5*13}\)
Dividing numerator and denominator by 13
=\(\frac{12}{5}\)
=2\(\frac{2}{5}\) min
