Verified Answer :

TheHero

F = K\(\frac{q1 q2}{r^2}\)

F =  1/(4 3.14 8.85 * 10^-12)   [ (1.6x 10^-19)^2/(4 x 10 ^-15)^2 ]  = 14.394 N

Answer:

F = 14.4 N

Explanation:

As we know that the force between two charge particles is given by coulombs law as

\(F_e = \frac{kq_1q_2}{r^2}\)

here we have

\(q_1 = q_2 = e\)

also we have

\(r = 4 \times 10^{-15} m\)

now we will have

\(F = \frac{(9\times 10^9)(1.6 \times 10^{-19})(1.6 \times 10^{-19})}{(4 \times 10^{-15})^2}\)

\(F = 14.4 N\)

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