Verified Answer :

Using E=hν where h is Planck's constant and v is the frequency of the photon. In the question above,the wavelenght is given so we can find the frequency of the photon using c=λν. c is a constant =310^8 so frequency is equal to
(310^8)/0.13510^-9. Then use ur frequency in the eqn above using h 6.62610^-34

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Answer:

884.9×10^3 KJ mol-1

Explanation:

From E= hf

E= Energy of the photon

h= Plank's constant

f= frequency of the radiation

But f= c/λ

c= speed of light

λ= wavelength

Hence

E= hc/λ

E= 6.63×10^-34 × 3×10^8/135×10^-12

E= 147×10^-17 × 6.02×10^23

E= 884.9×10^3 KJ mol-1

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