The completely factored polynomials are \(\boxed{2x\left( {{x^2} - 4} \right)}\) and \(\boxed{\left( {4x + 4} \right)\left( {x + 1} \right)}\). Option (b) and option (c) are correct.
Further Explanation:
Given:
The options are as follows,
(a). \(121{x^2} + 36{y^2}\)
(b). \(\left( {4x + 4} \right)\left( {x + 1} \right)\)
(c). \(3{x^4} - 15{n^3} + 12{n^2}\)
(d). \(3{x^4} - 15{n^3} + 12{n^2}\)
Calculation:
In option (a)
The expression \(121{x^2} + 36{y^2}\) is not in the factored form. option (a) is not correct.
In option (b)
The expression \(\left( {4x + 4} \right)\left( {x + 1} \right)\) is in the factored form.
\({\text{Factored}} = 4{\left( {x + 1} \right)^2}\)
Option (b) is correct.
In option (c)
The expression \(2x\left( {{x^2} - 4} \right)\) is in the factored form.
\(\begin{aligned}{\text{Factored}} &= 2x\left( {{x^2} - 4} \right)\\&= 2x\left( {x + 2} \right)\left( {x - 2} \right)\\\end{aligned}\)
Option (c) is correct.
In option (d)
The expression \(3{x^4} - 15{n^3} + 12{n^2}\) is not in the factored form.
Option (d) is not correct.
The completely factored polynomials are \(\boxed{2x\left( {{x^2} - 4} \right)}\) and \(\boxed{\left( {4x + 4} \right)\left( {x + 1} \right)}.\) Option (b) and option (c) are correct.
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Exponents and Powers
Keywords: solution, factored, completely, polynomial, factorized form, expression, difference of cubes, exponents, power, equation, power rule, exponent rule.