4NH₃ + 6NO → 5N₂ + 6H₂O
mol of NO = \(\frac{mass of NO}{Molar Mass of NO}\)
= \(\frac{27.8 g}{30.01 g / mol}\)
= 0.93 mol
Based on the balance equation mole ratio of NH₃ : NO is 4 : 6
= 2 : 3
If mol of NO = 0.93 mol
then mol of NH₃ = \(\frac{0.93 mol * 2}{3}\)
= 0.62 mol
Mass of ammonia = mol × molar mass
= 0.62 mol × 17.03 g/mol
= 10.54 g
Therefore B is the best answer
