Verified Answer :

mol of Na =  \(\frac{Mass of Na}{Molar Mass of Na}\)
 
                =  \(\frac{3.00g}{23.00g/mol}\)
 
                =  0.13 mol

# atoms of Na =  mol ×  avogadro's constant
  
                       =  0.13 mol  ×  [6.02 × 10²³]
 
                       =  7.83 × 10²²