Sam claims that his cat can do single-digit multiplication. He shows the cat 10 cards with simple multiplication problems that are either correct or incorrect. The cat correctly identifies the correctness of the card 7 times out of 10. If the cat were simply guessing, how many would the cat be expected to get correct?
Answer:
The cat is expected to get correct is:
5
Step-by-step explanation:
Sam claims that his cat can do single-digit multiplication.
He shows the cat 10 cards with simple multiplication problems that are either correct or incorrect.
Since, there are 50% chances of a question being correct or incorrect.
i.e. the probability of a answer being correct or incorrect is:
1/2
Also there are total 12 questions.
Hence, the expected value of the cat being correct after guessing is:
\(E(x)=\sum xp(x)\)
where x denote the event and the probability of an event.
Here x denote the question and p(x) it's probability.
Hence, the expected value is:
\(\dfrac{1}{2}\times 10=5\)
Hence, the cat is expected to get correct is:
5
Answer: The cat would expect 5 correct answers.
Step-by-step explanation:
Since we have given that
Total number of cards = 10
Answers are either correct or incorrect.
and the cat correctly identifies the correctness of the card 7 times out of 10.
Expected value will be
\(E(x)=\sum xp(x)\)
Here, x is the number of answers and P(x) is the probability of getting correct answer.
Here, we have x = 10
Probability the cat would get correct = \(\frac{1}{2}\)
So, expected value will be
\(\frac{1}{2}\times 10\\\\=5\)
Hence, The cat would expect 5 correct answers.