In a photograph, a house is 4 inches wide and 6 inches tall. The photograph is enlarged while keeping proportional dimensions, and the width of the house in the enlarged photograph is 9 inches. What is the height of the house in the enlarged photograph?

Since the width is enlarged by a specific amount, the height has the be enlarged by the same amount. 9÷4=2.25. Since the width was enlarged by 2.25, the height should be enlarged by the same amount. Multiply 6 and 2.25, and you would get 6×2.25=13.5.

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anjithaka anjithaka · Answer 2 · 2022-07-24T05:06:22-04:00

The height of the house in the enlarged photograph is 13.5cm.

How to estimate height of the house in the enlarged photograph?

Since the width exists enlarged by a specific amount, the height contains the be enlarged by the exact amount.

Let the height be x.

$$\frac{4}{6}=\frac{9}{x}$

Cross multiply

4x = 54

Divide both sides by 4

$$\frac{4 x}{4}=\frac{54}{4}$

Simplify

$$x=\frac{27}{2}$

To estimate undefined (singularity) points: x = 0.

Combine undefined points with solutions:

$$x=\frac{27}{2}$

x = 13.5

Therefore, the height of the house in the enlarged photograph is 13.5cm.

To learn more about algebraic expression

https://brainly.com/question/4541471

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