The velocity of an object increases from -10 m/s to -15 m/s in 2.0 s. What is the average acceleration of the object?
Average acceleration is given by:
a_average = V2 - V1/dt = -15 +10/2 = -2.5 m/s^2
Answer:
\(a=-2.5 \ m/s^2.\)
Explanation:
It is given that.
Initial velocity, \(v_i=-10\ m/s\).
Final velocity, \(v_f=-15 \ m/s\).
Also, time taken during the process, \(t=2.0 \ s\).
So, average acceleration, a is given by:
\(a=\dfrac{v_f-v_i}{t}\)
Putting all the given values in above equation.
\(a=\dfrac{-15-(-10)}{2} \ m/s^2=-2.5 \ m/s^2.\)
Hence, it is the required solution.