Answer:
The period of the given function is \(2\pi\)
Step-by-step explanation:
Given : Function \(y=1+\tan(\frac{1}{2}x)\)
To find : What is the period of the function?
Solution :
The general form of the tangent function is \(f(x)=A+B\tan(Cx)\)
Where, Period of the tangent function is \(P=\frac{\pi}{|C|}\)
Now, Compare the general form with the given function.
\(y=1+\tan(\frac{1}{2}x)\)
A=1 , B=1 , \(C=\frac{1}{2}\)
Period of the function is
\(P=\frac{\pi}{|C|}\)
\(P=\frac{\pi}{|\frac{1}{2}|}\)
\(P=2\pi\)
So, The period of the given function is \(2\pi\)
