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For the reaction P4+6Cl2 yields 4pcl3, determine how many moles of Cl2 would be needed to react with 3 moles of P4 to entirely use up all phosphorous.

Verified Answer :

TheHero

1 mole of P4 need to react with 6 moles

1 => 6
3 => x

x = 3 * 6/ 1=  18 moles

sebassandin

Answer:

\(n_{Cl_2}=18molCl_2\)

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

\(P_4+6Cl_2-->4PCl_3\)

In such a way, if 3 moles of P₄ are reacting, the needed moles of Cl₂ to completely consume them turn out:

\(n_{Cl_2}=3molP_4*\frac{6molCl_2}{1molP_4}\ _{Cl_2}=18molCl_2\)

This is done by realizing that 1 mole of P₄ needs 6 moles of Cl₂ to take the reaction to completion.

Best regards.

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