Answer: The answer is \(5x^3-22x^2+28x-8\) and \(25x^3-70x^244x-8.\)
Step-by-step explanation: We are given to write a polynomial of degree 3 whose only roots are 2 and \(\dfrac{2}{5}.\) Also, we need to find another polynomial of degree 3, if exists, that has the same roots.
The polynomial will be given by
\(p(x)=(x-2)(x-2)(x-\dfrac{2}{5})\\\\\Rightarrow 5p(x)=(x^2-4x+4)(5x-2)\\\\\Rightarrow P(x)=5x^3-20x^2+20x-2x^2+8x-8\\\\\Rightarrow P(x)=5x^3-22x^2+28x-8.\)
The other polynomial with same roots exist and is given by
\(q(x)=(x-2)(x-\dfrac{2}{5})(x-\dfrac{2}{5})\\\\\Rightarrow 25q(x)=(x-2)(5x-2)^2\\\\\Rightarrow Q(x)=(x-2)(25x^2-20x+4)\\\\\Rightarrow Q(x)=25x^3-20x^2+4x-50x^2+40x-8\\\\\Rightarrow Q(x)=25x^3-70x^244x-8.\)
