jeramyahmelton
Answered

Suppose the probability that it rains in the next two days 1/3 for tomorrow and 1/6"for the day after tomorrow. What is P(rain tomorrow, then rain the day after tomorrow)?


A.1/2

B.1/18

C.2/9

D.1/9

Verified Answer :

TheHero

This events are separate , so the probability of both of which combined is the product of them.

Let P(A) rain tomorrow event
      P(B) rain after tomorrow event

P(A) = 1/3

P(B) = 1/6

P(A in B) = P(A) P(B) = 1/3 1/6= 1/18   

Choice: (B)

Answer:

\(\frac{1}{18}\)

Step-by-step explanation:

Probability that it rains tomorrow P(A)=  \(\frac{1}{3}\)

Probability that it rains day after tomorrow P(B)= \(\frac{1}{6}\)

So, P(rain tomorrow, then rain the day after tomorrow)

\(P(A) \times P(B)\)

\(\frac{1}{3} \times \frac{1}{6}\)

\(\frac{1}{18}\)

Hence P(rain tomorrow, then rain the day after tomorrow) is \(\frac{1}{18}\)

So, Option B is correct.