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If the weight of an object is greater than the buoyant force acting on it, it will sink. What is the weight of a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g.


Hint: Convert mass to weight using F = mg, where mass is in kilograms and g = 9.80 m/s2.

a)213 g

b)0.213 kg

c)2.09 N

d)2,090 N

Verified Answer :

Edufirst

Answer: option c) 2.09 N


Explanation:


The weight of a block of iron with the dimensions 3.00 cm × 3.00 cm × 3.00 cm, and that has a mass of 213 g may be calculated using the given hint: convert mass to weight using F = mg, where mass is in kilograms and g = 9.80 m/s².


  • First, convert the mass in grams to kilograms: 213 g × 1 kg / 1000 g = 0.213 kg

  • Weight = F = mg = 0.213 kg × 9.80 m/s² = 2.0874 N

  • Round to three signficant figures: 2.09 N

Answer:

Weight of the block of iron is 2.09 N

Explanation:

If the weight of an object is greater than the buoyant force acting on it, it will sink. The dimension of the box is 3.00 cm x 3.00 cm x 3.00 cm.

Mass of the box, m = 213 g

Converting it into kg, m = 0.213 kg

Using second law of motion, F = W = mg

W = 0.213 kg × 9.8 m/s²

W = 2.0874 N

or W = 2.09 N

Hence, the correct option is (c) " 2.09 N ".

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