a load of 45 N attached to a spring that is hanging vertically stretches the spring 0.14 m. What is the spring constant?
Answer:
Spring constant, k = 321.42 N/m
Explanation:
Force acting on spring, F = 45 N
Displacement caused due to stretching, x = 0.14 m
Using Hooke's law :
\(F=-kx\)
Where
k is the spring constant
\(k=\dfrac{F}{x}\)
\(k=\dfrac{45\ N}{0.14\ m}\)
k = 321.42 N/m
Hence, this is the required solution.
The spring constant is 321.4 N/m.
Given that the force attached to the spring is 45N and the stretch length of the spring is 0.14 m.
The spring constant can be calculated using Hooke's Law which is given below.
\(F = -kx\)
Where F is the force on the spring, k is the spring constant and x is the stretched length of the spring.
Substituting the values in the above formula.
\(45 = - k \times 0.14\)
\(k = - 321.4 \;\rm N/m\)
Hence we can conclude that the spring constant is 321.4 N/m.
To know more about the spring constant, follow the link given below.
https://brainly.com/question/4291098.