How do I solve this equation? 3|13-2t|=15
/ 13 - 2t / = 15 ÷ 3 ;/ 13 - 2t / = 5 ;13 - 2t = + 5 or 13 - 2t = -5 ;First equation, -2t = - 8; t = 4 ;Second equation, -2t = - 18 ; t = 9 ;The solutions are 4 and 9 .
\(3 |13 - 2t | =15\) ⇒ \(|13-2t| = 15\div3\) ⇒ \(\boxed {|13-2t| = 5}\)\(\hbox {We have two equations : 1. } |13-2t|=5\) \(2.|13-2t|=-5\)\(\hbox{The first: }\) ⇒ \(13-2t=5\) ⇒ \(2t=13-5\) ⇒ \(2t=8\) ⇒ \(\boxed {t=4}\)\(\hbox { The second: } 13-2t=-5\) ⇒ \(2t=13-(-5)=18\) ⇒ \(\boxed {t=9}\)