How do I solve: x/3 +10= 15
x/3+10=15 -10 -10x/3= 5x= 3*5x=15check by substitution 15/3 +10= 15 5+10=15, this is true Therefore x=15 is the answer
\(\frac{x}{3}+10=15 \hbox{ /|10 (substract 10 from both) }\)\(\frac{x}{3}=15-10=5\) ⇒ \(x=3*5\)\(\boxed {x=15}\)