How many moles of h2so4 is produced from 12.5 moles of so2?
Moles ratio:
S + 2 H2SO4 = 3 SO2 + 2 H2O
2 moles H2SO4 ------------ 3 moles SO2
moles H2SO4 --------------- 12.5 moles SO2
moles H2SO4 = 12.5 x 2 / 3
moles H2SO4 = 25 / 3
=> 8.33 moles of H2SO4
The moles of sulfuric acid produced from the balanced chemical equation are 12.5 mol.
The equation for the production of sulfuric acid is given as:
\(\rm 2\;SO_2\;+\;O_2\;+\;2\;H_2O\;\rightarrow\;2\;H_2SO_4\)
From the balanced chemical equation, for the production of 2 moles of sulfuric acid, 2 moles of sulfur dioxide is required.
The moles of sulfuric acid produced from 12.5 moles of sulfur dioxide are:
\(\rm 2\;mol\;SO_2=2\;mol\;H_2SO_2\\12.5\;mol\;SO_2=\dfrac{2}{2}\;\times\;12.5\;mol\;H_2SO_4\\ 12.5\;mol\;SO_2=12.5\;mol\;H_2SO_4\)
The moles of sulfuric acid produced from 12.5 moles sulfuric acid is 12.5 mol.
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