find the quotient and the remainder: (x^2+3x-4)/(x-1)
Evaluate this...\(\frac{x^2+3x-4}{x-1}\)the x at the bottom cancels out one of the xs at the top so it will be\(\frac{x^2+2x-4}{-1}\)Now the one cancels out one of the 1s in the -4 so\({x^2+2x-3}\)Hope this helps :)