3(2-b) < 10-3(b-6) please help
3(2-b)<10-3(b-6)6-b<5(b-6)6-b<5b-30Let's make "b".......26-(2)<5(2)-304<10-304<-20In this case, this is a false statement. You can make "b" any number and I chose 2. I hope this helped!
first you distribut the 3 into (2-b) then distribute -3 into (b-6)to get 6-3b<10-3b+18then simplify-3b+3b>10+18-6 0>22