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Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-6+(n-1)(1/5)

A5, -5 1/5, 1 4/5.
B-6, -5 1/5, -4
C0, 3/5, 1 4/5
D-6, -5 2/5, -4 1/5

Verified Answer :

answer is D. -6, -5 2/5, -4 1/5

A(1)=-6+(1-1)(1/5) = -6 + 0 = -6
A(4)=-6+(4-1)(1/5) = -6 + 3/5 = - 5 2/5
A(10)=-6+(10-1)(1/5) = -6 + 9/5 = -4 1/5
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