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agenttex5460
agenttex5460 agenttex5460
  • 25-01-2017
  • Mathematics
Answered

What are the solutions of the equation: z^2 - 12z + 36 = 0? 

A-6, 6
B6, 6
C6, -6
D-6, -6

Verified Answer :

WillieH
WillieH WillieH
  • 25-01-2017

Factor by groups
(Z^2 -6z) (-6z+36)
GCF 1st binomial is z
GCF of 2nd binomial is -6
(z-6)(z-6)
Solutions
6,6

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