Let
\(A(0,3) B(1,1)\)
Step 1
Find the slope of the line
we know that
the formula to calculate the slope between two points is equal to
\(m=\frac{(y2-y1)}{(x2-x1)}\)
substitute the values
\(m=\frac{(1-3)}{(1-0)}\)
\(m=\frac{(-2)}{(1)}\)
\(m=-2\)
Step 2
Find the y-intercept
we know that
the y-intercept is the value of y when the value of x is equal to zero
in this problem the y-intercept is the point \(A(0,3)\)
Step 3
Find the equation of the line into slope-intercept form
we know that
the equation of the line into slope-intercept form is equal to
\(y=mx+b\)
we have
\(m=-2\)
\(b=3\) -----> b is equal to the y-coordinate of the y-intercept
substitute
\(y=-2x+3\)
therefore
the answer is the option A
\(y=-2x+3\)
