Answer:
The range of the function is {24,18,12,6,0}
Step-by-step explanation:
Given : The range of the function \(f(x)=12-3x\) for the domain {-4, -2, 0, 2, 4}.
To find : What is the range ?
Solution :
We have given the domain of the function so to find range we have to substitute the value of x i.e. domain,
\(f(x)=12-3x\)
For x=-4,
\(f(4)=12-3(-4)\)
\(f(4)=12+12\)
\(f(4)=24\)
For x=-2,
\(f(4)=12-3(-2)\)
\(f(4)=12+6\)
\(f(4)=18\)
For x=0,
\(f(4)=12-3(0)\)
\(f(4)=12+0\)
\(f(4)=12\)
For x=2,
\(f(4)=12-3(2)\)
\(f(4)=12-6\)
\(f(4)=6\)
For x=4,
\(f(4)=12-3(4)\)
\(f(4)=12-12\)
\(f(4)=0\)
So, The range of the function is {24,18,12,6,0}
