Verified Answer :

scme1702

We sill use the formula:
Q = nl, where Q is the heat, n is the number of moles and l is the latent molar heat of fusion of water.

moles = mass / Mr
n = 40 / 18
n = 2.22 moles

Q = 2.22 x 6.01
Q = 13.34 kJ of heat must be removed

ShyzaSling

We will use the formula Q = nl, where Q is the heat, n is the number of moles and l is the latent molar heat of fusion of water.


The formula to calculate moles is moles = mass / Mr, so n = 40 / 18 which comes out to be 2.22 moles.


Now we can calculate the heat, Q = 2.22 x 6.01. So 13.34 kJ of heat must be removed in order to freeze a tray of ice of 40 g