Answer : The number of carbon atoms present in butane are \(4.14\times 10^{22}\)
Explanation : Given,
Molar mass of \(C_4H_{10}\) = 58.1 g/mole
Mass of \(C_4H_{10}\) = 1.00 g
First we have to calculate the number of moles of butane.
\(\text{Moles of }C_4H_{10}=\frac{\text{Mass of }C_4H_{10}}{\text{Molar mass of }C_4H_{10}}\)
\(\text{Moles of }C_4H_{10}=\frac{1.00g}{58.1g/mole}=0.0172mole\)
Now we have to calculate the number of carbon atoms present in butane.
In butane, there are 4 atoms of carbon and 10 atoms of hydrogen.
As we know that, 1 mole of substance contains \(6.022\times 10^{23}\) number of atoms.
As, 1 mole of butane contains \(4\times 6.022\times 10^{23}\) number of carbon atoms.
So, 0.0172 mole of butane contains \(0.0172\times 4\times 6.022\times 10^{23}=4.14\times 10^{22}\) number of carbon atoms.
Therefore, the number of carbon atoms present in butane are \(4.14\times 10^{22}\)