An orchestra has twice as many woodwind instruments as brass instruments. There are a total of 150 brass and woodwind instruments. Write two different addition equations that describes this situation. Use w for woodwinds and b for brass
Answer: The two different addition equations that describes the given situation are,
w = 2 b
b + w = 150
Step-by-step explanation:
Here, w represents the number of woodwinds and b represents the number of brass instrument.
Since, There are twice as many woodwind instruments as brass instruments,
⇒ w = 2b
And, The total number of instruments = 150
⇒ w + b = 150
Hence, the equations that shows the given situation are,
w = 2 b, b + w = 150
Answer:
\(w+b=150\)
Or
\(2b+b=150\)
Step-by-step explanation:
Given : An orchestra has twice as many woodwind instruments as brass instruments. There are a total of 150 brass and woodwind instruments.
To Find: Write two different addition equations that describes this situation.
Solution:
Let w be the woodwinds instruments..
Let b be the brass instruments.
We are given that An orchestra has twice as many woodwind instruments as brass instruments.
So, \(w = 2b\)
We are given that There are a total of 150 brass and woodwind instruments.
So, \(w+b=150\)
Or
\(2b+b=150\)
Hence two different addition equations that describes this situation are :
\(w+b=150\)
Or
\(2b+b=150\)