You want to create an ID code for the students in your school based on three characters. The first and second characters must be a letter of the alphabet, and the third must be a digit between 1 and 9 inclusive. To find out how many different codes there are, would a list or tree diagram be practical in this case? Why or why not?

a list would work so much better cause u can list all the possibilities and the diagram would be no help in this case because a diagram is only going to show u certain parts when u can get all answers from a list.

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virtuematane virtuematane · Answer 2 · 2019-04-26T02:49:51-04:00

Answer with explanation:

As we know that there are 26 letters in a alphabet and we are asked to use 9 digits in the third place.

So, the total number of such cases possible are or the total number of codes than can be created using a letter in the first two place and a digit in the third place are:

26×26×9=6084

( Since in the first place there are a choice of 26 letters and for the second place again we have a choice of 26 letters as it is not mentioned that the repetition is not allowed and for the third place we have 9 choices)

Hence, to represent these 6084 cases via tree diagram is too complex and difficult as it will have too many branches.

Also, the listing of these cases could be done by computer but manually listing these cases is too tiring and time taking.