The sum of two numbers is 94. The larger number is 8 less than twice the smaller number. What is the larger number?
x - the larger number
y - the smaller number
The larger number is 8 less than twice the smaller number:
\(x=2y-8\)
So the larger number is 2y-8.
The sum of the two numbers is 94.
\(2y-8+y=94 \\
2y+y=94+8 \\
3y=102 \\
y=\frac{102}{3} \\
y=34\)
The smaller number is 34.
\(x=2y-8=2 \times 34-8=68-8=60\)
The larger number is 60.
\(a+b=94\)
\(a>b\) ⇒ \(a=2b-8\)
\(\hbox{We will introduce this in the first, original equation} : 2b-8+b=94\)
\(3b=102\) ⇒ \(b= \frac{102}{3}\) ⇒ \(\boxed{b=34}\)
\(a=94-34\) ⇒ \(\boxed{a=60}\)