Answered

Ka, the acid dissociation constant, for an acid is 9 × 10^{−4} at room temperature. At this temperature, what is the approximate percent dissociation of the acid in a 1.0 M solution?

A0.03%
B0.09%
C3%
D5%
E9%

Can you please explain with some details?

Verified Answer :

jydclix

dissociation=k×no of moles
percentage of dissociation=9.0×10^-4×1×100
knowing that x%=x/100,we then say;
x/100=9.0×10^-4×1×100
therefore, x=100×100×9×10^-4×1
x=9
x percentage of dissociation=9%

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