When the Kelvin temperature of an enclosed gas doubles, the particles of the gas . (1 point)

move faster

strike the walls of the container with less force

decrease in average kinetic energy

decrease in volume

The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. How (1 point)
The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. How

does the gas pressure change?

(1 point)

It increases by a factor of four.

It decreases by a factor of eight.

It increases by a factor of eight.

It increases by a factor of two.

Charles's law states that . (1 point)

the pressure of a gas is inversely proportional to its temperature in kelvins

the volume of a gas is directly proportional to its temperature in kelvins

the pressure of a gas is directly proportional to its temperature in kelvins

the volume of a gas is inversely proportional to its temperature in kelvins

A sample of gas occupies 17 mL at –112°C. What volume does the sample occupy at 70°C? (1 point)

10.6 mL

27 mL

36 mL

8.0 mL

The combined gas law relates which of the following? (1 point)

pressure and volume only

temperature and pressure only

volume and temperature only

temperature, pressure, and volume

As we know that the kinetic energy of the particle of the gas is directly proportional to the temperature of the gas. That means higher the temperature higher will be the kinetic energy.

When the Kelvin temperature of an enclosed gas doubles, the kinetic energy will be double and then the particles of the gas move faster.

Answer 2 : The correct option is, It increases by a factor of eight.

Explanation :

According to the Boyle's law, the volume of the gas is inversely proportional to the pressure of the gas at constant temperature and the number of moles of gas.

\(\frac{P_{final}}{P_{initial}}=\frac{V_{initial}}{V_{final}}\)

\(\frac{P_{final}}{P_{initial}}=\frac{4L}{0.5L}=8\)

Hence, the gas pressure change increases by a factor of eight.

Answer 3 : The correct option is, the volume of a gas is directly proportional to its temperature in kelvins.

According to the Charles's law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure and the number of moles of gas.

\(V\propto T\)

\(\frac{V}{T}=k\)

Answer 4 : The correct option is, 36 ml

Solution : Given,

initial volume = 17 ml

initial temperature = \(-112^oC=273+(-112)=161K\)

final temperature = \(70^oC=273+70=343K\)

Formula used : \(\frac{V_{final}}{V_{initial}}=\frac{T_{final}}{T_{initial}}\)

\(\frac{V_{final}}{17ml}=\frac{343K}{161K}\)

\(V_{final}=36ml\)

Therefore, the volume of the sample occupy at \(70^oC\) is, 36 ml

Answer 5 : The correct option is, temperature, pressure, and volume

Explanation :

Combined gas law is the combination of the Boyle's law, Charles's law and Gay Lussac's law at constant number of moles of gas.

\(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\)

The variable used in the combined gas law are temperature, pressure, and volume
.