Let \(x\) be the larger number and \(y\) the smaller number.
The first sentence translates to \(x=8+3y\). The second translates to \(x+y=52\).
Since \(x=8+3y\), you can substitute this into the second equation to get
\((8+3y)+y=4y+8=52\implies 4y=44\implies y=11\)
Then substituting this into the original second equation gives
\(x+11=52\implies x=41\)
