for ax²+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
so
12x²-17x+6=0
a=12
b=-17
c=6
x=\(\frac{-(-17)+/- \sqrt{(-17)^2-4(12)(6)} }{2(12)}\)
x=\(\frac{17+/- \sqrt{289-288} }{24}\)
x=\(\frac{17+/- \sqrt{1} }{24}\)
x=\(\frac{17+/- 1}{32}\)
x=\(\frac{17+1}{32}\) or \(\frac{17-1}{32}\)
x=\(\frac{18}{32}\) or \(\frac{16}{32}\)
x=9/16 or 1/2
