16x^2+8x+1 =0 use quadratic formula to determine the root. express in fraction form
the answer would be -1/4. go to a web site called math way it will make it easier
for ax²+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
so
16x²+8x+1=0
a=16
b=8
c=1
x=\(\frac{-(8)+/- \sqrt{(8)^2-4(16)(1)} }{2(16)}\)
x=\(\frac{-8+/- \sqrt{64-64} }{32}\)
x=\(\frac{-8+/- \sqrt{0} }{32}\)
x=\(\frac{-8+/- 0}{32}\)
x=\(\frac{-8}{32}\)
x=-1/4