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A 0.100-kilogram apple hangs in a tree 1.50 meters above the ground. Ignoring frictional effects, the total mechanical energy of the apple is _____.


0.00 J

less than 1.47 J but more than 0.00 J

exactly 1.47 J

more than 1.47 J

Verified Answer :

mgh (.19.81.5
it would be exactly 1.47

Answer: The total mechanical energy stored in an apple is 1.47 Joules

Explanation:

Mass of the apple = 0.100 kg

Height at which apple is hanging = 1.50 m

Force on the apple = \(Mass \times g\)

Velocity of the apple = 0 m/s

g = acceleration due gravity

Mechanical energy = Potential energy + Kinetic energy

= \(mass\times g\times height\) + \(\frac{1}{2}mass\times (velocity)^2\)

\(=0.100 kg\times 9.8 m/s^2\times 1.50 m+\frac{1}{2}\times 0.100 kg\times (0 m/s)^2=1.47 Joules\)

The total mechanical energy stored in an apple is 1.47 Joules